18^(x)^2+4x+4=18^9x+18

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Solution for 18^(x)^2+4x+4=18^9x+18 equation:



18^(x)^2+4x+4=18^9x+18
We move all terms to the left:
18^(x)^2+4x+4-(18^9x+18)=0
We add all the numbers together, and all the variables
4x+18^x^2-(18^9x+18)+4=0
We get rid of parentheses
4x+18^x^2-18^9x-18+4=0
We add all the numbers together, and all the variables
4x+18^x^2-18^9x-14=0
We move all terms containing x to the left, all other terms to the right
4x+18^x^2-18^9x=14

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